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| Användare | Inlägg | |
|---|---|---|
| ANDERStG | 2009-10-18 20:41 | |
 | Pseudo: Du sa att jag var den enda... | |
| kajix | 2009-10-18 20:44 | |
 | "Vargen vet även att Rödluvan bantar, så hon kunde max äta upp ett kex." hmmm | |
| ANDERStG | 2009-10-18 20:45 | |
| kajix har rätt, undertoner rakt från 50-talet. :) | |
| amandahug - Ej medlem längre | 2009-10-18 20:47 | |
 | Apropå detta, blev jag påmind om en historia som min vän Urban, legenden, berättat: A physics student was asked to describe a method by which the height of a building could be determined using a barometer "You tie a long piece of string to the neck of the barometer, then lower the barometer from the roof of the skyscraper to the ground. The length of the string plus the length of the barometer will equal the height of the building." This highly original answer so incensed the examiner that the student was failed. The student appealed on the grounds that his answer was indisputably correct, and the university appointed an independent arbiter to decide the case. The arbiter judged that the answer was indeed correct, but did the problem it was decided to call the student in and allow him six minutes in which to provide a verbal answer which showed at least a minimal familiarity with the basic principles of physics. For five minutes the student sat in silence, forehead creased in thought. The arbiter reminded him that time was running out, to which the student replied that he had several extremely relevant answers, but couldn't make up his mind which to use. On being advised to hurry up the student replied as follows: "Firstly, you could take the barometer up to the roof of the skyscraper, drop it over the edge, and measure the time it takes to reach the ground. The height of the building can then be worked out from the formula H = 0.5g x t squared. But bad luck on the barometer." "Or if the sun is shining you could measure the height of the barometer, then set it on end and measure the length of its shadow. Then you measure the length of the skyscraper's shadow, and thereafter it is a simple matter of proportional arithmetic to work out the height of the skyscraper." "But if you wanted to be highly scientific about it, you could tie a short piece of string to the barometer and swing it like a pendulum, first at ground level and then on the roof of the skyscraper. The height is worked out by the difference in the gravitational restoring force T = 2 pi sqroot (l / g)." "Or if the skyscraper has an outside emergency staircase, it would be easier to walk up it and mark off the height of the skyscraper in barometer lengths, then add them up." "If you merely wanted to be boring and orthodox about it, of course, you could use the barometer to measure the air pressure on the roof of the skyscraper and on the ground, and convert the difference in millibars into feet to give the height of the building." "But since we are constantly being exhorted to exercise independence of mind and apply scientific methods, undoubtedly the best way would be to knock on the janitor's door and say to him 'If you would like a nice new barometer, I will give you this one if you tell me the height of this skyscraper'." | |
| Pseudonymf | 2009-10-18 20:48 | |
 | Rödluvan är rädd för figuren. Och ett gram extra för henne kan ju faktiskt sluta i att vargen äter upp henne. Amanda, en översättning till tyska skulle nog locka mig att orkar läsa allt som stod ;) | |
| Pseudonymf | 2009-10-18 20:49 | |
| ➤ANDERStG 2009-10-18 20:41: “Pseudo: Du sa att jag var den enda...” Du ÄR den enda. Forever and ever. När ska vi gå på bio? :D | |
| Pseudonymf | 2009-10-18 20:50 | |
| Nu vill jag att ni ska få tänka till lite: Låt F1 vara en godtycklig konvex fyrhörning. För k>1, Fk konstrueras genom att man skär Fk-1 i två delar längs en av dess diagonaler, vänder på en av delarna och sedan klistrar delarna samman längs samma diagonal. Bestäm det största möjliga antalet icke-kongruenta fyrhörningar i följden {Fk}. | |
| amandahug - Ej medlem längre | 2009-10-18 20:51 | |
| 463 st? (en chansning) | |
| Pseudonymf | 2009-10-18 20:52 | |
| Du är ingen riktig matematiker. Inte som min favoritprofessor som alltid gav mig höga betyg: www.linnaeus.uu.se/o...ne wton.jpg | |
| ANDERStG | 2009-10-18 20:55 | |
| 3? | |
| Pseudonymf | 2009-10-18 20:55 | |
| När ni skriver frågetecken så gör det mig orolig :S | |
| ANDERStG | 2009-10-18 20:56 | |
| 4! | |
| ANDERStG | 2009-10-18 20:56 | |
| Alltså 4. | |
| Pseudonymf | 2009-10-18 20:58 | |
| Lösning: Notera att om sidlängderna hos fyrhörningen är a, b, c, d, så finns exempel, där följden av fyrhörningar innehåller 6 icke-kongruenta: de med olika ordning på sidorna. Tag nämligenen fyrhörning med alla sidor olika, men som ändå påminner om en kvadrat (detta för att fyrhörningarna som bildas inte ska bli icke-konvexa). | |
| ANDERStG | 2009-10-18 21:01 | |
| Pseudo: (a,b,c,d) = (1,2,3,4) Ge mig de 6 icke-kongruenta möjligheterna. | |
| Smutsig Djur - Ej medlem längre | 2009-10-18 21:01 | |
| Ni är ju nördar ju. Dagens upptäckt. | |
| ANDERStG | 2009-10-18 21:02 | |
| Jag ser 1,2,3,4 1,2,4,3 1,4,2,3 1,3,4,2 Vad missar jag? | |
| ANDERStG | 2009-10-18 21:07 | |
| Jag tror du får kontakta författaren av den specifika uppgiften. | |
| Pseudonymf | 2009-10-18 21:08 | |
| mattebloggen.com/200...-v ecka-25/ | |
| amandahug - Ej medlem längre | 2009-10-18 21:08 | |
| Smutsig Djur 2009-10-18 21:01: “Ni är ju nördar ju. Dagens upptäckt.” Grattis, du har just gjort motsvarigheten till att upptäcka sand i Sahara! | |
